If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12y^2+43y+14=0
a = 12; b = 43; c = +14;
Δ = b2-4ac
Δ = 432-4·12·14
Δ = 1177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-\sqrt{1177}}{2*12}=\frac{-43-\sqrt{1177}}{24} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+\sqrt{1177}}{2*12}=\frac{-43+\sqrt{1177}}{24} $
| y=5.8=3/20 | | 6–g=19 | | 3/7t+9=0 | | 16y+5=85 | | 29=11+6p | | 24y^2+86y+27=-1 | | 32=10+2n | | g/3+46=55 | | 1=9-2y | | 4=20-4m | | 1−5x+8+6x=7+x+1 | | 7+3j=16 | | 7y+6=0 | | 1/12=x/21 | | 20=4b-12 | | 27x+7=20x+42 | | 1=p-5 | | 40=5q+15 | | 3=9-g | | 6=15-p | | a=3.3-17 | | 24=7v+3 | | X+48+x=180 | | x^2-13=29 | | |x2+10x-4|=20 | | d/2+13=16 | | 21=7+2u | | 16x=5x+84 | | 5=9-d | | 4(3k-5k)=92 | | 2x-8(x+6)=0 | | -3+w/2=-5 |